Friday, July 31, 2009

Fall Schedule

I am updating this from John. A Logan library. I came here to complete some paper work and get the books for my fall class. I have now set aside my office hr and every thing. The two classes I am teaching are Math 52 and Math 62. Basically Introductory and Intermediate Algebra. I am excited about how my schedule looks like because I think I can make a difference here as making this part of math fun for my students where so many without right guidance develops aversion for math.

Thursday, July 30, 2009

Barrow's Cosmic Imagery


Tuesday, July 28, 2009

Why



One reason people love mathematics is the way it gives insight in to things. Here is one celebrated result of what sum(1/k^2,k=1..infinity) is. It all depends on knowing sin(x)/x. The limit(sin(x)/x,x=0) =1 but for each integral multiple of Pi it is 0. Thus we have . This is also called as basel problem and it was genius of Euler who came up with this neat solution.

Thursday, July 23, 2009

Stewart's book review




Monday, July 20, 2009

Tekkonkinkreet



Well another Manga Novel I read last week. I had to read it twice. There are several characters and almost two story lines which run parallel. The black and white's and Kimura's, rat and snake.



Sunday, July 19, 2009

day today

Read some more of Ian Stewart's book and worked out some easy problems like the one on Diophantine's birthday. Finished the Fermat's last theorem section on the book. It's funny it reads pretty much what I have read in several other book but still Stewart's exposition is better than others. Did bicycle ride in the morning to vine with Yi, Rachel, Ping and Zing. Went to Evan's house. Then to Carbondale library. Got the book "Meta Math ! The quest for Omega". Read the first chapter there and its interesting. Now at Morris to return few DVDs. Then off to meditate with the group.

Thursday, July 16, 2009

Finding area of irregular figure on a grid



I was reading Ian Stewart's book and came across this interesting result. Where you can find the area of any such bounded picture just by counting the number of (B) boundary dots and (I) inside dots. The relation is 1/2*B+I-1. The distance between the adjacent dots is 1 unit.

So in this case there are 21 boundary dots. 5 inside dots. Therefore area is 1/2*21-5+1 = 7.5

Saturday, July 11, 2009

Tatsumi


Wednesday, July 08, 2009

Beamer links

If you need simple examples
Compare various themes
Excellent tutorial
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