April 27, 2005
I am right now in library and decided to update this blog. Well today's morning was sweet as I could prove one more exercise on Golden Number. It was to prove that
F(n-1)*F(n+1) = F(n)^2 + (-1)^n
Another property of Golden numbers is
(Phi)^(n+1) = F(n) + Phi *F(n+1)
More stuff in complex number was discussed today, including one more of hadamard's theorem. I still have to get the grasp of laurent series and residue stuff. Dr. Grimmer discussed more on the higher order differential equations.
I have to return the book Div, Grad, Curl and all that.
Time to go and catch Lou Dobb's tonight and I am hungry too !!
F(n-1)*F(n+1) = F(n)^2 + (-1)^n
Another property of Golden numbers is
(Phi)^(n+1) = F(n) + Phi *F(n+1)
More stuff in complex number was discussed today, including one more of hadamard's theorem. I still have to get the grasp of laurent series and residue stuff. Dr. Grimmer discussed more on the higher order differential equations.
I have to return the book Div, Grad, Curl and all that.
Time to go and catch Lou Dobb's tonight and I am hungry too !!
posted by Sumant at 4:41 PM
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